Monday, May 11, 2009

5/11/09

Hey guys!

So today, we finished correcting the worksheet "Electric Potential"

1) V = PE/Q
5.0x10-18/1.6x10-19
= 31V

2a) ( 9x109)(2X10-16)(2X10-10)
= 3.6X10-12
(3.6X10-12)(0.01)
= 3.6X10-14 JOULES
2b) V=PE/q
= 3.6x10-14/2.0x10-16
= 180V

3)Ek= qV
(1.6x10-19)(1000 V)
= 1.6 x 10-16J
Ek= 1/2 mv2
v= sqrt( 2(1.6x10-16/9.11x10-31)
= 1.9x107 m/s
4) V= kQq/r
=9x109 (3.0)(1.6X10-19)/ 0.80
= 5.4 x10-9
V= kQq/r
= 9x109 (3.0)(1.6X10-19)/ 0.5
= 8.64x10-9

W= V2-V1
= 8.64x10-9 - 5.4 x10-9
= 3.24x10-9 J

5a) W= qV
= (1.6x10-19)(12)
= 1.92x10-19J
OR
= (1.92x10-18J/ 1.6x10-19 )
= 12eV electronvolt
b) same amount = 1.92x10-18J or 12eV

c) Ek= 1/2mv2
= sqrt( 2(1.92x10-18/ 9.11x10-31)
v= 2.05x106 m/s

after we corrected the worksheet, we did a lab:

Chapter 21: Charges, Energy, Voltage

which is due tomorrow, so don't forget to hand it in.
Also don't forget to do your research paper, its due Friday !

George will scribe tomorrow, since he didn't do it last week =P

* correct my mistakes when you see some , please and thanks*

=)

2 comments:

hao said...

i think the last answer should be 2.05*10^-6

Ms K said...

Thanks, Hao, I'll change the answer.