Corrections...

hello....

Today in class Mrs. K corrected the last 6 questions (11-16) from the worksheet called " Moving Charges" and the corrections are on Mrs. K slide .

Also we corrected The path of a Charged Particle in a Magnetic Field and Review worksheets



Review...

1) R = mv/Bq
= (9.11x10^-31 )(2.0x10⁶ )/(8.0x10^-2)(1.6x10^-19)
= 1.42x10⁴ m

2) v = E/B
= 5.0x10^-4/3.0x10^-2
= 1.67x10⁶ m/s

# 3, 4, 9 and 10 you don't have to do it

5) v = BqR/m
= (5.0x10^-4)(1.6x10^-19)(0.03)/9.11x10^-31
= 2.63x10⁶ m/s

6) a.
v = BqR/m
= (3.0x10^-2)(1.6x10^-19)(1.5x10^-2)/1.67x10^-27
= 4.3x10⁴ m/s

b. E = V.B
= 4.3x10⁴/3.0x10^-2
= 1.3x10³ N/C

7. m = BqR/v
= (0.28)(1.6x10^-19)(0.30)/7.0x10⁵
= 1.92x10^-26 kg

8) for this question calculate the velocity using the formula below

v = BqR/m
= (0.030)(1.6x10^-19)(8.0x10^-3)/9.11x10^-31
= 4.4x10⁷ m/s

then substitute the velocity to the formula below to find the radius

R = mv/Bq
= (1.6x10^-27)(4.4x10⁷)/(0.03)(1.6x10^-19)
= 14.66 m

Reminder:
-test on tuesday... Good Luck!!

the next scribe will be KimC
have a great long weekend everyone :D