Monday, July 6, 2009
Wednesday, June 10, 2009
6/10/09
Hello everyone =) in today's class, we went over the physics exam review "MECHANICS".
Things to know:
- question #8 will not be on the exam=)
- when solving question #13, you must know vertical / horizontal velocity
- use newtons 2nd law for question #14
- both question 15 & 16 are momentum questions
- remember for question 17 , when force and distance are the same direction, no work is done
- know work , force, distance for question 18
- question 19 is energy over time
- question #20 , add the areas together
- question #21 is potential energy
- question #22 is kinetic energy
- use newtons second law for question 23
- for question #24 , use hooks law
- question 25 is a spring potential energy question
In the past few days this week, we corrected our last test. You will find the corrections on the blog. We also went over some of the exam review questions.
Since a lot of people will be away tomorrow, we will go over the fields question on Friday =)
have fun studying=)
Oh and Jasmin will scribe tomorrow =)
Things to know:
- question #8 will not be on the exam=)
- when solving question #13, you must know vertical / horizontal velocity
- use newtons 2nd law for question #14
- both question 15 & 16 are momentum questions
- remember for question 17 , when force and distance are the same direction, no work is done
- know work , force, distance for question 18
- question 19 is energy over time
- question #20 , add the areas together
- question #21 is potential energy
- question #22 is kinetic energy
- use newtons second law for question 23
- for question #24 , use hooks law
- question 25 is a spring potential energy question
In the past few days this week, we corrected our last test. You will find the corrections on the blog. We also went over some of the exam review questions.
Since a lot of people will be away tomorrow, we will go over the fields question on Friday =)
have fun studying=)
Oh and Jasmin will scribe tomorrow =)
Tuesday, June 9, 2009
Thursday, June 4, 2009
June 4 2009
Hello everybody.
This is Hao. : )
We talk about the answers of the phyz book ( green book) today.
P532
1. EMF=BLV=(4*10^-2 T)(31m)(15m/s)=18.6V
2. EMF=BLV=(0.5 T)( 20m)(4m/s)=40V
3. EMF=BLV=(4.5*10^5 T)(75m)(950000m/3600s)=0.89V
4. a. EMF=BLV=(0.3T)(0.75m)(16m/s)=3.6V
b. I=V/R=3.6V/11Ω=0.33A
5. EMF=BLV=(0.32T)(0.4m)(1.3m/s)=0.17V
I=V/R=0.17V/10Ω=0.017A
14. a. X/150 = 625V/120V
X= 781.25 turns
b. X/150 = 35V/120V
X= 43.75 turns
c. X/150 = 6V/120V
X= 7.5 turns
15. a. X/120v = 1200/80
X=1800V
b. Pp = Ps = (I s)(V s) = (2A)(18000V)=3600w
Ip=Pp/Vp =(3600w)/(120v)=30A
c. Pp=Ps =(Is)(Vs)=(2A)(1800V)=3600W
16. a. X/475 = 9V/120V
X=35.625
b. Ps=(Vs)(Is)=(9v)(0.125A)=1.125W=Pp
Pp= (Vp)(Ip)
Ip=Pp/Vp=1.125w/120v=9.375*10^-3A
P533
20. a. Pp=Ps=150W= (Is)(Vs)=(5A)(Vs)
Vs=150W/5A=30V Bigger than 9V
So, step up
b. 30V/9V = 10/3
21. Pp=(Ip)(Vp)=(3A)(12V)=36W=Ps
Vs=Ps/Is=36W/0.75A=48W
Tp/Ts = Vp/ Vs
Tp= (Vp/Vs)(Ts)=(12V/48V)(1200)=300 turns
we will have unit test tomorrow. good luck everybody......
This is Hao. : )
We talk about the answers of the phyz book ( green book) today.
P532
1. EMF=BLV=(4*10^-2 T)(31m)(15m/s)=18.6V
2. EMF=BLV=(0.5 T)( 20m)(4m/s)=40V
3. EMF=BLV=(4.5*10^5 T)(75m)(950000m/3600s)=0.89V
4. a. EMF=BLV=(0.3T)(0.75m)(16m/s)=3.6V
b. I=V/R=3.6V/11Ω=0.33A
5. EMF=BLV=(0.32T)(0.4m)(1.3m/s)=0.17V
I=V/R=0.17V/10Ω=0.017A
14. a. X/150 = 625V/120V
X= 781.25 turns
b. X/150 = 35V/120V
X= 43.75 turns
c. X/150 = 6V/120V
X= 7.5 turns
15. a. X/120v = 1200/80
X=1800V
b. Pp = Ps = (I s)(V s) = (2A)(18000V)=3600w
Ip=Pp/Vp =(3600w)/(120v)=30A
c. Pp=Ps =(Is)(Vs)=(2A)(1800V)=3600W
16. a. X/475 = 9V/120V
X=35.625
b. Ps=(Vs)(Is)=(9v)(0.125A)=1.125W=Pp
Pp= (Vp)(Ip)
Ip=Pp/Vp=1.125w/120v=9.375*10^-3A
P533
20. a. Pp=Ps=150W= (Is)(Vs)=(5A)(Vs)
Vs=150W/5A=30V Bigger than 9V
So, step up
b. 30V/9V = 10/3
21. Pp=(Ip)(Vp)=(3A)(12V)=36W=Ps
Vs=Ps/Is=36W/0.75A=48W
Tp/Ts = Vp/ Vs
Tp= (Vp/Vs)(Ts)=(12V/48V)(1200)=300 turns
we will have unit test tomorrow. good luck everybody......
June 3 2009
I was so ready to go to sleep.. not only did it slip my mind, but it flew out of it, crashed into a garbage can, met a homeless person, made friends with a mime, took a taxi but, got hit by a train, broke a leg, joined the paraolympics, won silver losing to a Japanese woman, retired, got married to a platypus, discovered a world in a wardrobe, and finally found its way back to my head, but had a fight, argued for days, went out for dinner, asked to come back home, ate a lobster and finally decided to finish this scribe post together.
Answers to Chapter 26 Review
1.EMF=Blv
EMF=(4x10^-3T)(0.05m)(2.5m/s)
EMF= 5x10^-4 V
2.EMF=Blv
EMF=(4x10^-5T)(2m/s)(0.07m)
EMF=1.12x10^-5 V
l=v/R
l=1.12x10^-5 V/0.5
l=2.2x10^-5 A
3.CC is down EC is up
6. South ^ ^ ^ North
8.a)V=P/l
V=1500 Watts/175 A
V= 8.57
9.a)Np/Ns=Np/Vs
1/2500=1200/Vs
Vs=300 000
b)Pp=Ps
Pp=IpVp
Pp=15 A x 120 V
Pp=18 000 W
Ps=IpVp
18 000=(Ip)(300 000)
Ip=0.06 A
c)p=IV
p=(300 000)(0.06)
p=18 000 W
-----------------------------------------------------
"A transformer does not create or destroy energy, a transformer only converts voltage and current"
- Ms.Kozoriz
We completed Chapter 37: Electromagnetic Induction Transformers, Ms.Kozoriz has posted the answers on the blog rendering it useless to give you the answers myself.
She presented to us a copper coiled magnetic flashlight (CCMF for short) using the power of inserting a magnet into a copper coil.. that`s as far as i can explain.
If you must study for the Physics Test, a list of problems are provided in the green book to help prepare you for the test:
Ch.25
Reviewing Concepts: 1, 2, 3, 10, 14 p.530
Applying Concepts: 13 p.531
Problems 1-5, 14-16, 20, 21 p.532-533
Answers to Chapter 26 Review
1.EMF=Blv
EMF=(4x10^-3T)(0.05m)(2.5m/s)
EMF= 5x10^-4 V
2.EMF=Blv
EMF=(4x10^-5T)(2m/s)(0.07m)
EMF=1.12x10^-5 V
l=v/R
l=1.12x10^-5 V/0.5
l=2.2x10^-5 A
3.CC is down EC is up
6. South ^ ^ ^ North
8.a)V=P/l
V=1500 Watts/175 A
V= 8.57
9.a)Np/Ns=Np/Vs
1/2500=1200/Vs
Vs=300 000
b)Pp=Ps
Pp=IpVp
Pp=15 A x 120 V
Pp=18 000 W
Ps=IpVp
18 000=(Ip)(300 000)
Ip=0.06 A
c)p=IV
p=(300 000)(0.06)
p=18 000 W
-----------------------------------------------------
"A transformer does not create or destroy energy, a transformer only converts voltage and current"
- Ms.Kozoriz
We completed Chapter 37: Electromagnetic Induction Transformers, Ms.Kozoriz has posted the answers on the blog rendering it useless to give you the answers myself.
She presented to us a copper coiled magnetic flashlight (CCMF for short) using the power of inserting a magnet into a copper coil.. that`s as far as i can explain.
If you must study for the Physics Test, a list of problems are provided in the green book to help prepare you for the test:
Ch.25
Reviewing Concepts: 1, 2, 3, 10, 14 p.530
Applying Concepts: 13 p.531
Problems 1-5, 14-16, 20, 21 p.532-533
Wednesday, June 3, 2009
Tuesday, June 2, 2009
Scribe Post MONDAY
Ugh almost forgot about this.
The Answers to the Electromagnetic Induction sheet
v = 100km/h x 1h/3600s x 1000m/1km = 280m/s
EMF = Blv = (5x10^(-5)*T)(70m)(280m/s) = 1.0V
EMF = Blv = (0.025Wb/m^2)(0.10m)(0.75m/s)
EMF = Blv = (0.45N/A*m)(0.15m)(0.3m/s)
= 2.0 x 10^(-2) V
EMF = Blv = (0.02T)(0.05m)(0.1m/s)
= 1 x 10^(-4) V
EMF = -N(delta phi/delta t) = -325 (1.15 x 10 ^(-5) WB / 1.0 x 10^(-3)s)
EMF = -3.74V
N = EMF/(deta phi/delta t) = 0.25V/((5x10^(-3))/1s) = 50 turns
phi = 8A
EMF = -N ((BA)/delta t) = -75 [ ( 1.5(Wb/m^2) x 4m^2 x ((m^2) / 10^4 m^2) / 2.5 x 10^(-2) s) ]
EMF = -1.8V
Reviewed Lenz's law, which basically states that the direction that the poles are moving in relation to the current changes wether the current flows clockwise or counterclockwise. Lenz's law states:
"For a current induced by a conductor by a changing magnetic field, the current is in such a direction that its own magnetic field opposes the charge that produced it."
In laymans terms, the current flows in a direction that causes the magnetic field to be the opposite of the field that created it.
We did a quick worksheet on Lenz's law, then got an exam review and a sheet on Transformers (robots in disguise).
Study up for the exam!
Sunday, May 31, 2009
SCRIBE POST Thursday/Friday
I don't see anyone doing it, so I guess I'll take initiative, because I don't want to keep wishing and waiting.
From what I recall, unless I mixed up the days, Ms. K wasn't there but, Ms. K was there! Don't question that... it does, technically make sense. xD
But yes, I do believe we watched another Same-Same guy video on electromagnetic induction and had to write eight points on it and handed it in. Funny though, I could've sworn that the video was REALLY familiar. I have a feeling I watched it last sem during gr. 11 physics.
On Friday's class, we spent the first couple of minutes and filled in more blanks in the study guide and finished the Chapter 37: Electromagnetic Induction
The correct circled answers were:
1. related/
From what I recall, unless I mixed up the days, Ms. K wasn't there but, Ms. K was there! Don't question that... it does, technically make sense. xD
But yes, I do believe we watched another Same-Same guy video on electromagnetic induction and had to write eight points on it and handed it in. Funny though, I could've sworn that the video was REALLY familiar. I have a feeling I watched it last sem during gr. 11 physics.
On Friday's class, we spent the first couple of minutes and filled in more blanks in the study guide and finished the Chapter 37: Electromagnetic Induction
The correct circled answers were:
1. related/
the motion of electric charges/
the motion of a magnet/
magnetic field in the loop/
electromagnetic induction
2. doubles/
doubles/
electric field/
magnetic field [although baseball is acceptable xD haa]/
electromagnetic waves.
Then afterwards... we were assigned to read an information sheet regarding EMF, and to have answered most of the worksheet questions on Electromagnetic Induction by Monday. Then we sort of... dispersed into a foreign land-- the quad and had a lovely class time. We should do it again **hint hint** it's quite lovely outside. nyar.
Thursday, May 28, 2009
Physics Class May 27, 2009
GREETINGS FELLOW PHYSICISTS.
On May 27th we continued our work on electric circuits.
2) must have a changing magnetic flux
Factors that determine the value of the induced EMF
1) length of the wire
2) flux density of the field
3) speed at which conductor moves though the field
EMF = Blv
~Katherine~
On May 27th we continued our work on electric circuits.
We went over the following:
- Resistivity Problems.
- Chapter 25 Study Guide.
- Electric Circuit Problems.
We received the following:
- Cross-Word Puzzle.
- Notes on Electromagnetic Induction.
Here is a summary of the notes:
Induced current
A current set up in a closed circuit located in a magnetic field whenever the total magnetic flux linking the circuit is changing.
Necessary conditions for an electric current to be produced with a magnetic field
1) must have a closed circuit2) must have a changing magnetic flux
Factors that determine the value of the induced EMF
1) length of the wire
2) flux density of the field
3) speed at which conductor moves though the field
EMF = Blv
- Some of us also rewrote the test on Electric and Magnetic Fields.
~Katherine~
Wednesday, May 27, 2009
Niwatori-san's corner (Ohm's Law and Circuits sounds electrifying LOL)
Annyong-hi jumushyossoyo?
( Korean for Did you sleep well? / Good morning phrase in Korean)
Back to physics, sorry I couldn't make it early for my blog but I was reformatting my computer and it took long than I had anticipated. (Don't ask plz -___- )
Anywho Quoting Pacifico's last post just in the morning also, I want to say that the answers for the textbook questions from 2 days back are on Pacifico's scribe post so say thanks to Pacifico for his contribution.
Other than that a new set of new info was given by the title "2.0 Resistance, Ohm's Law and Resistivity"
It is an elaboration to Ohm's Law V / I = R
Adding Resistivity to the formulae of the Resistance R = p*L / A
where "p" is the proportionality resistivity constant, "L" is the Length of the resistance and "A" is Amperes or current flowing through the resistance.
For now ill close out Annyong-hi kashipshio ( Good bye in Korean =) )
Next scribe is Moofatt like pacifico said...
*rolls into a ball and summersaults to class*
( Korean for Did you sleep well? / Good morning phrase in Korean)
Back to physics, sorry I couldn't make it early for my blog but I was reformatting my computer and it took long than I had anticipated. (Don't ask plz -___- )
Anywho Quoting Pacifico's last post just in the morning also, I want to say that the answers for the textbook questions from 2 days back are on Pacifico's scribe post so say thanks to Pacifico for his contribution.
Other than that a new set of new info was given by the title "2.0 Resistance, Ohm's Law and Resistivity"
It is an elaboration to Ohm's Law V / I = R
Adding Resistivity to the formulae of the Resistance R = p*L / A
where "p" is the proportionality resistivity constant, "L" is the Length of the resistance and "A" is Amperes or current flowing through the resistance.
For now ill close out Annyong-hi kashipshio ( Good bye in Korean =) )
Next scribe is Moofatt like pacifico said...
*rolls into a ball and summersaults to class*
Early Morning Unemotional Scribe Post.
What happened today:
p.670(?), #35 a. - d.
For the Handouts, if you were absent, be sure to ask:
Next scribe is:
Ryan MOOffatt
- We went over the circuit questions from the "duck book" (p.670, #35, a. - c. if I recall correctly) that Miss Kozoriz assigned us to do. Then added in question number 35.d.
- And gave us handouts.
p.670(?), #35 a. - d.
a.
| Volts (V) | Current/I (A) | Resistance (Ω) | |
| Resistor1 | 24 | 38 | 8 |
| R2 | 9 | 38 | 3 |
| R3 | 21 | 38 | 7 |
| RTotal | 54 | 38 | 18 |
b.
| Volts (V) | Current/I (A) | Resistance (Ω) | |
| Resistor1 | 9 | 2 | 4.5 |
| R2 | 9 | 2 | 4.5 |
| RTotal | 9 | 4 | 2.25 |
c.
| Volts (V) | Current/I (A) | Resistance (Ω) | |
| Resistor1 | 24.2 | 0.92 | 25 |
| R2 | 2402 | 1.61 | 15 |
| R3 | 25.8 | 2.58 | 10 |
| RTotal | 50 | 2.58 | 19.4 |
d.
| Volts (V) | Current/I (A) | Resistance (Ω) | |
| Resistor1 | 75 | 3 | 25 |
| R2 | 20 | 2 | 10 |
| R3 | 5 | 1 | 5 |
| R4 | 1 | 1 | 15 |
| RTotal | 9 | 3 | 21.67 |
For the Handouts, if you were absent, be sure to ask:
- 2.0 Resistance, Ohm's Law and Resistivity
- Grade 12 Electric Circuits: Resistivity Problems
- Table 14.4: Factors that Affect Resistance
- Fundamentals of Physics: An Introductory Course (Factors Affecting Resistance)
Next scribe is:
Ryan MOOffatt
Tuesday, May 26, 2009
Scribe!!
Hey everyone it's me Aldrin B. scribing for yesterday's class...
At the start of the class Ms. K gave back our test papers..
woooo... scary!!XD.. She also gave us the answers....
refer to slide 5/25/09 posted by Ms K.
after that, we were asked to answer the problems on the handout she gave last friday.
Simple Circuits (#'s 1 & 2 a-f)
1. Three 10Ω resistors are connected in series to a 12-V battery.
a. Draw a diagram of the circuit.
(-----series circuit diagram----)to be posted
b. What is the total resistance of the circuit.
RT = 10Ω + 10Ω + 10Ω
= 30Ω
c.What is the total current in the circuit?
I = V/R
= 12V/30Ω
=0.4A
d. what is the potential drop across each resistor?
V= IR
=(0.4A)(10Ω)
=4V
e. What is the current in each resistor?
I=V/R
=12V/30Ω
=0.4A
f. What is the power dissipated by each resistor?
P=IV
=0.4A(4V)
=1.6W
2. Three 10Ω resistors are connected in parallel to a 12-V battery.
a. Draw a diagram of the circuit.
(-----parallel circuit diagram----)to be posted
b. What is the total resistance of the circuit?
1/R = 1/10 + 1/10 + 1/10
= 3/10
R/1 = 10/3 = 3.3Ω
c. What is the total current in the circuit?
I=V/R
=12V/3.3Ω
=3.6A
d. What is the potential drop across each resistor?
(-----------------------------------------)
e. What is the current in each resistor?
I=V/R
= 12V/10Ω
=1.2A
f. What is the power dissipated by each resistor?
P=IV
=1.2A(12V)
=14.4W
We then answered problems regarding compound circuits.??
well, thats all I remember. i'll put more information as soon as I get home.
*** i think we have an assignment about the problems on the big book***:)?
see you all in class!!!
At the start of the class Ms. K gave back our test papers..
woooo... scary!!XD.. She also gave us the answers....
refer to slide 5/25/09 posted by Ms K.
after that, we were asked to answer the problems on the handout she gave last friday.
Simple Circuits (#'s 1 & 2 a-f)
1. Three 10Ω resistors are connected in series to a 12-V battery.
a. Draw a diagram of the circuit.
(-----series circuit diagram----)to be posted
b. What is the total resistance of the circuit.
RT = 10Ω + 10Ω + 10Ω
= 30Ω
c.What is the total current in the circuit?
I = V/R
= 12V/30Ω
=0.4A
d. what is the potential drop across each resistor?
V= IR
=(0.4A)(10Ω)
=4V
e. What is the current in each resistor?
I=V/R
=12V/30Ω
=0.4A
f. What is the power dissipated by each resistor?
P=IV
=0.4A(4V)
=1.6W
2. Three 10Ω resistors are connected in parallel to a 12-V battery.
a. Draw a diagram of the circuit.
(-----parallel circuit diagram----)to be posted
b. What is the total resistance of the circuit?
1/R = 1/10 + 1/10 + 1/10
= 3/10
R/1 = 10/3 = 3.3Ω
c. What is the total current in the circuit?
I=V/R
=12V/3.3Ω
=3.6A
d. What is the potential drop across each resistor?
(-----------------------------------------)
e. What is the current in each resistor?
I=V/R
= 12V/10Ω
=1.2A
f. What is the power dissipated by each resistor?
P=IV
=1.2A(12V)
=14.4W
We then answered problems regarding compound circuits.??
well, thats all I remember. i'll put more information as soon as I get home.
*** i think we have an assignment about the problems on the big book***:)?
see you all in class!!!
Monday, May 25, 2009
Sunday, May 24, 2009
Hi... ^^ uhm,, I forgot to scribe last Thursday.. I'm sorry ,, my bad.. oh well,, last Thursday... we did a lab about circuits... Basically, the purpose of that lab is for us to know the difference between the series cicuits and Parallel circuits.. We spent the whole class doing the lab and answering questions regarding it..
For Friday,, Ms. K. gave the answers for the study guide... (I'll post the answers tomorrow... ^^)
Also she gave us some worksheets to do as homework... Yeheyyy!!! (??) and we answered sheet 34-1 - 35-2 .... here it is..
For Friday,, Ms. K. gave the answers for the study guide... (I'll post the answers tomorrow... ^^)
Also she gave us some worksheets to do as homework... Yeheyyy!!! (??) and we answered sheet 34-1 - 35-2 .... here it is..
that's it... have a wonderful weekend... see you guys on Monday...
next scribe is ALDRIN B. ^^,
Wednesday, May 20, 2009
hi...!!!!
In today's class:
-we watched a video (electrical current)
- jot down 6-7 info....
- received the following worksheets
-Direction of the electrical current
- transparency worksheet and..
- chapter 23 study guide
The following were the answers in the Transparency Worksheet
1.Which symbol represents a battery?Draw it in the space provided.
2. Draw the symbol thjat represent and instrument that measures current.
3. How would you show that an electric connection exist
4. if you illustrated a circuit that included a lamp dimmer ,what symbol you use for the resistor.
5. Draw a circuit that includes the following :a switch ,a battery, and a lamp
6.If you wanted to measure the voltage in the circuit in question 5,what symbol would you add?
That's what we all did for today's class......the next scribe will be arjeannelle..
Friday, May 15, 2009
Corrections...
hello....
Today in class Mrs. K corrected the last 6 questions (11-16) from the worksheet called " Moving Charges" and the corrections are on Mrs. K slide .
Also we corrected The path of a Charged Particle in a Magnetic Field and Review worksheets
Review...
1) R = mv/Bq
= (9.11x10-31 )(2.0x106 )/(8.0x10-2)(1.6x10-19)
= 1.42x104 m
2) v = E/B
= 5.0x10-4/3.0x10-2
= 1.67x106 m/s
# 3, 4, 9 and 10 you don't have to do it
5) v = BqR/m
= (5.0x10-4)(1.6x10-19)(0.03)/9.11x10-31
= 2.63x106 m/s
6) a.
v = BqR/m
= (3.0x10-2)(1.6x10-19)(1.5x10-2)/1.67x10-27
= 4.3x104 m/s
b. E = V.B
= 4.3x104/3.0x10-2
= 1.3x103 N/C
7. m = BqR/v
= (0.28)(1.6x10-19)(0.30)/7.0x105
= 1.92x10-26 kg
8) for this question calculate the velocity using the formula below
v = BqR/m
= (0.030)(1.6x10-19)(8.0x10-3)/9.11x10-31
= 4.4x107 m/s
then substitute the velocity to the formula below to find the radius
R = mv/Bq
= (1.6x10-27)(4.4x107)/(0.03)(1.6x10-19)
= 14.66 m
Reminder:
-test on tuesday... Good Luck!!
the next scribe will be KimC
have a great long weekend everyone :D
Today in class Mrs. K corrected the last 6 questions (11-16) from the worksheet called " Moving Charges" and the corrections are on Mrs. K slide .
Also we corrected The path of a Charged Particle in a Magnetic Field and Review worksheets
Review...
1) R = mv/Bq
= (9.11x10-31 )(2.0x106 )/(8.0x10-2)(1.6x10-19)
= 1.42x104 m
2) v = E/B
= 5.0x10-4/3.0x10-2
= 1.67x106 m/s
# 3, 4, 9 and 10 you don't have to do it
5) v = BqR/m
= (5.0x10-4)(1.6x10-19)(0.03)/9.11x10-31
= 2.63x106 m/s
6) a.
v = BqR/m
= (3.0x10-2)(1.6x10-19)(1.5x10-2)/1.67x10-27
= 4.3x104 m/s
b. E = V.B
= 4.3x104/3.0x10-2
= 1.3x103 N/C
7. m = BqR/v
= (0.28)(1.6x10-19)(0.30)/7.0x105
= 1.92x10-26 kg
8) for this question calculate the velocity using the formula below
v = BqR/m
= (0.030)(1.6x10-19)(8.0x10-3)/9.11x10-31
= 4.4x107 m/s
then substitute the velocity to the formula below to find the radius
R = mv/Bq
= (1.6x10-27)(4.4x107)/(0.03)(1.6x10-19)
= 14.66 m
Reminder:
-test on tuesday... Good Luck!!
the next scribe will be KimC
have a great long weekend everyone :D
Thursday, May 14, 2009
Just a random question
Hi ms. K ! I'm just wondering, is the research paper supposed to be one page double space, or one page single space?
Today. ;D
This is Ann here and I'm your scribe for today. Awesome.
Today we didn't do very much. Ms. K corrected a worksheet. It was called 'Moving Charges' or at least that's what it says on the slides that Ms. K posted up. Check your work and do corrections if you havent done them already.
Ms. K also gave out 2 worksheets today. Pick them up if you haven't yet.
Our research paper is due tomorrow. Hand it in, it's work lots of marks !
Reminder that our test on this current unit is on Tuesday. You have the whole long weekend to study physics. :D
The next scribe will be raminaR18. Have a nice time scribing tomorrow ;D
Today we didn't do very much. Ms. K corrected a worksheet. It was called 'Moving Charges' or at least that's what it says on the slides that Ms. K posted up. Check your work and do corrections if you havent done them already.
Ms. K also gave out 2 worksheets today. Pick them up if you haven't yet.
Our research paper is due tomorrow. Hand it in, it's work lots of marks !
Reminder that our test on this current unit is on Tuesday. You have the whole long weekend to study physics. :D
The next scribe will be raminaR18. Have a nice time scribing tomorrow ;D
Wednesday, May 13, 2009
Scribe Time!!
HEYYYYYYY!!!!!! It's me, Dion and I'm here to scribe!!!!!
First off in class we got back our lab sheets from, i believe it was tuesday we did them?....anywho.. here are the answers for it!
----------------------------------------------------------------------
Observations and Data
Level Charge (C) Voltage(J/C) Energy (J)
3v 4 3 12
6v 3 6 18
9v 2 9 18
12v 1 12 12
(You need to multiply charge by the voltage so the C's cancel out and your left with J.)
Analysis
1.
2. 18J
3. Because there is more than one charge in that voltage level.
4. 6J because each charge falling to the 6V level gives off 3J each.
Applications
1. A larger 12V battery holds more charges than 2 small 9V batteries.
----------------------------------------------------------------------
Well that's it for that sheet we then went over the Moving Charges Worksheet. Here are the answers for that sheet!!
----------------------------------------------------------------------
1a. Because the drop has had 2 electrons removed it becomes a positively charged. Because of gravity and that this charged particle will move towards the negative plate, the drop will move downwards.
1b. There are 2 forces acting on this little drop, the electric field force and the force of gravity. To solve for it, we need to figure out each of these forces and because they are going in the same direction we simply add them together.
Fg=mg=4.4x10^-14N Fe=Eq=9.5x10^-15
Fnet=Fg+Fe=5.35x10^-14N [down]
2. For this question, we need to solve for its final velocity. To do this we need to first find the force of the electric field. with that, we can then solve for acceleration of the electron. Once we have acceleration we can find the final velocity.
Fe=Eq=1.92x10^-16N a=Fe/m=2.1x10^14m/s^2
v2^2=v1^2+2ad=4.58x10^6m/s
3. For this question, we first need to figure out what the charge of 3 electrons is. Once we know this we can solve for the electric force and gravitational force acting upon it. Then just add them together and there is the force! Do not forget that the 2 forces act in different directions!!
q=(3)(1.6x10^-19)=4.8x10^-19
Fe=Eq=1.14x10^-14N Fg=mg=2.35x10^-13N
Fnet=Fg+(-Fe)=2.24x10^-13N[down]
The force is downwards because the force of gravity is the stronger force in this case.
4a. There are 2 forces acting on the sphere, gravity and electric field.
4b. Because the particle is stationary, and the force of gravity acts downwards, the sphere must be positively charged so it will go against the force of gravity causing it to remain motionless.
4c. To figure out the charge, we know both forces of gravity and electric forces are equal so we can rearrange the equations to make it do work for us.
Fg=Fe mg=Eq
q=mg/E=1.6x10^-18C
4d. To solve for the number of electrons, simply divide the charge by the constant for the charge of one electron.
N=q/e=10 electrons
----------------------------------------------------------------------
We then received one more sheet called Magnetic Formulae! This sheet contains numerous equations and is basically a review from what we did in grade 11 physics.
That's all we did for today so I'm off!! I choose the next scribe to be....Pacifico!
Tuesday, May 12, 2009
Monday, May 11, 2009
5/11/09
Hey guys!
So today, we finished correcting the worksheet "Electric Potential"
1) V = PE/Q
5.0x10-18/1.6x10-19
= 31V
2a) ( 9x109)(2X10-16)(2X10-10)
= 3.6X10-12
(3.6X10-12)(0.01)
= 3.6X10-14 JOULES
2b) V=PE/q
= 3.6x10-14/2.0x10-16
= 180V
3)Ek= qV
(1.6x10-19)(1000 V)
= 1.6 x 10-16J
Ek= 1/2 mv2
v= sqrt( 2(1.6x10-16/9.11x10-31)
= 1.9x107 m/s
4) V= kQq/r
=9x109 (3.0)(1.6X10-19)/ 0.80
= 5.4 x10-9
V= kQq/r
= 9x109 (3.0)(1.6X10-19)/ 0.5
= 8.64x10-9
W= V2-V1
= 8.64x10-9 - 5.4 x10-9
= 3.24x10-9 J
5a) W= qV
= (1.6x10-19)(12)
= 1.92x10-19J
OR
= (1.92x10-18J/ 1.6x10-19 )
= 12eV electronvolt
b) same amount = 1.92x10-18J or 12eV
c) Ek= 1/2mv2
= sqrt( 2(1.92x10-18/ 9.11x10-31)
v= 2.05x106 m/s
after we corrected the worksheet, we did a lab:
Chapter 21: Charges, Energy, Voltage
which is due tomorrow, so don't forget to hand it in.
Also don't forget to do your research paper, its due Friday !
George will scribe tomorrow, since he didn't do it last week =P
* correct my mistakes when you see some , please and thanks*
=)
So today, we finished correcting the worksheet "Electric Potential"
1) V = PE/Q
5.0x10-18/1.6x10-19
= 31V
2a) ( 9x109)(2X10-16)(2X10-10)
= 3.6X10-12
(3.6X10-12)(0.01)
= 3.6X10-14 JOULES
2b) V=PE/q
= 3.6x10-14/2.0x10-16
= 180V
3)Ek= qV
(1.6x10-19)(1000 V)
= 1.6 x 10-16J
Ek= 1/2 mv2
v= sqrt( 2(1.6x10-16/9.11x10-31)
= 1.9x107 m/s
4) V= kQq/r
=9x109 (3.0)(1.6X10-19)/ 0.80
= 5.4 x10-9
V= kQq/r
= 9x109 (3.0)(1.6X10-19)/ 0.5
= 8.64x10-9
W= V2-V1
= 8.64x10-9 - 5.4 x10-9
= 3.24x10-9 J
5a) W= qV
= (1.6x10-19)(12)
= 1.92x10-19J
OR
= (1.92x10-18J/ 1.6x10-19 )
= 12eV electronvolt
b) same amount = 1.92x10-18J or 12eV
c) Ek= 1/2mv2
= sqrt( 2(1.92x10-18/ 9.11x10-31)
v= 2.05x106 m/s
after we corrected the worksheet, we did a lab:
Chapter 21: Charges, Energy, Voltage
which is due tomorrow, so don't forget to hand it in.
Also don't forget to do your research paper, its due Friday !
George will scribe tomorrow, since he didn't do it last week =P
* correct my mistakes when you see some , please and thanks*
=)
Thursday, May 7, 2009
Electric and Magnetic Fields
hi there, it me, lorenz. i am the scribe for wednesday and for some reason George still hasn't post his blog for tuesday...
Anyways, so for the people who were not there yesterday, we handed in out "Concept Map for Radiation" and we answered 3 questions for a "Health Physics Reflection". She gave us some notes on "Electric and Magnetic Fields" , "Coulomb's Law in One Dimension" and a "Chapter 32: Electrostatics Coulomb's Law Worksheet". I asked ms. Kozoriz to post the notes that she wrote on the smart board and i hope that will help you more.
Don't forget to hand in your Health Physics Research on Friday, May 15.
the next scribe will be Daureen Joy Nacario.
see you guys later!!!
=)
Anyways, so for the people who were not there yesterday, we handed in out "Concept Map for Radiation" and we answered 3 questions for a "Health Physics Reflection". She gave us some notes on "Electric and Magnetic Fields" , "Coulomb's Law in One Dimension" and a "Chapter 32: Electrostatics Coulomb's Law Worksheet". I asked ms. Kozoriz to post the notes that she wrote on the smart board and i hope that will help you more.
Don't forget to hand in your Health Physics Research on Friday, May 15.
the next scribe will be Daureen Joy Nacario.
see you guys later!!!
=)
Wednesday, May 6, 2009
Monday, May 4, 2009
Effects of Radiation on Humans ...
Hi guys, this is Nelsa, (finally) scribing for Friday's class. Whoot, everybody rejoice, hahaha.
ANYWAYS.
On Friday, we read chapter 3 in our Health Physics duotang, so.. you should probably do that if you haven't already. We answered the questions on pages 36, 39 and 41, which Ms. K posted the answers to on the previous post.
We read about a new formula on Friday too, I(d) = Ioe^-ud, which can be used to mathematically determince the amount of gamma radiation a substance will absorb. In the equation, Io stands for the original number of gamma rays (or incident intensity), I(d) is the number of gamma rays that don't pass through the substance, d represents the thickness of the substance and the coefficient u depends on the amount of energy the gamma ray carries. The higher the energy, the smaller the absorption coefficient.
Aaaand yeah, that's it. Don't forget to do your 'Sort and Predict' sheet, I think it's due today.
Next scribe will be.. George.
Cool.
'Kay bye.
ANYWAYS.
On Friday, we read chapter 3 in our Health Physics duotang, so.. you should probably do that if you haven't already. We answered the questions on pages 36, 39 and 41, which Ms. K posted the answers to on the previous post.
We read about a new formula on Friday too, I(d) = Ioe^-ud, which can be used to mathematically determince the amount of gamma radiation a substance will absorb. In the equation, Io stands for the original number of gamma rays (or incident intensity), I(d) is the number of gamma rays that don't pass through the substance, d represents the thickness of the substance and the coefficient u depends on the amount of energy the gamma ray carries. The higher the energy, the smaller the absorption coefficient.
Aaaand yeah, that's it. Don't forget to do your 'Sort and Predict' sheet, I think it's due today.
Next scribe will be.. George.
Cool.
'Kay bye.
Friday, May 1, 2009
Thursday, April 30, 2009
April 30, 09
Haha, eyo guys! Suzette is here! Sorry for posting this thing so late. I'm a busy girl... we can't do anything about it. LOL!
oKaY,
Today, we got our "Exploration of Space & Low Earth Orbit" test back; and we corrected it. (as you can see, Ms. K kindly posted the answers below). Next, we went over the "Activity: X-ray Analysis". It's on the Health Physics booklet on page 10. We identified the possible problems in each x-rays.
Then, we were told to read Chapter Two of Health Physics booklet (that's if you've finished reading the first chapter.) At the same time, Ms. K gave us an activity worksheet: "Sort and Predict" and that's it.
It's probably too late already but just in case...
Reminder: Compare and Contrast worksheet is due tomorrow and Sort and Predict on Monday.
And uhh... the NEXT SCRIBE IS.. (drum roll please)
dun dun dun dun....
The beautiful witch of the south, NELSA! haha
oKaY,
Today, we got our "Exploration of Space & Low Earth Orbit" test back; and we corrected it. (as you can see, Ms. K kindly posted the answers below). Next, we went over the "Activity: X-ray Analysis". It's on the Health Physics booklet on page 10. We identified the possible problems in each x-rays.
Then, we were told to read Chapter Two of Health Physics booklet (that's if you've finished reading the first chapter.) At the same time, Ms. K gave us an activity worksheet: "Sort and Predict" and that's it.
It's probably too late already but just in case...
Reminder: Compare and Contrast worksheet is due tomorrow and Sort and Predict on Monday.
And uhh... the NEXT SCRIBE IS.. (drum roll please)
dun dun dun dun....
The beautiful witch of the south, NELSA! haha
Wednesday, April 29, 2009
Monday, April 27, 2009
Repentence for being late...
Yeah, my bad on not scribing for Friday. Totally forgot about it. Well i remembered now and I'm doing the post for today and Friday.
So on Friday, let see what we did on Friday.... I think we watched a movie, hoping that I'm right, more about the gravitational stuff and things alike and the we went over the questions on the review 8. If you want the answers, it's on Mrs Kozoriz's Slides. Then we had a bit of review on the derivatives of the formulas that we're using and that was Friday.
Today, we watched a movie about the... kc135, I think, (man, i have the worst memory ever) and basically took notes and things alike on that. The movie talked about a couple people making this project so they could go a "zero grav" situation to test out their experiment. The thought that light would give of light the same way and the heat would not make the air rise. Seems that the heat was pretty much equally distributed in "zero grav".
And that's what we did today, good luck on the test tomorrow and next sci be is ALDRIN S, MUHAHHA you have to double scribe like me.
So on Friday, let see what we did on Friday.... I think we watched a movie, hoping that I'm right, more about the gravitational stuff and things alike and the we went over the questions on the review 8. If you want the answers, it's on Mrs Kozoriz's Slides. Then we had a bit of review on the derivatives of the formulas that we're using and that was Friday.
Today, we watched a movie about the... kc135, I think, (man, i have the worst memory ever) and basically took notes and things alike on that. The movie talked about a couple people making this project so they could go a "zero grav" situation to test out their experiment. The thought that light would give of light the same way and the heat would not make the air rise. Seems that the heat was pretty much equally distributed in "zero grav".
And that's what we did today, good luck on the test tomorrow and next sci be is ALDRIN S, MUHAHHA you have to double scribe like me.
Thursday, April 23, 2009
Wednesday, April 22, 2009
042209 A visit from Mr. Same-same
Hey guys, it's Ms. "trips-a-lot". So if your here I guess your wondering what we did today.
Let me recall;
- We watched Mr. Same-same, Mr. Same-same talked about satellite motion. And took ten points on the video. Geeze I handed in my points to the Ms.K and I can't really remember what exactly what it was about. I don't want to tell you the wrong thing so. Well anyways if you missed it you should ask her to let her see if you can watch. It was really helpful.
-Then we corrected the Concept-Development Practice Page: Chapter 14: Satellite Motion
I'm really sorry about my spelling. I can't spell for squat. If anybody can't understand just leave a comment and I'll try to fix it to the best of my abilities.
I think I cover everything we did today.
Finish your chapter 8 review
TEST TUESDAY APRIL 28, 2009
The next scribe is John.
Let me recall;
- We watched Mr. Same-same, Mr. Same-same talked about satellite motion. And took ten points on the video. Geeze I handed in my points to the Ms.K and I can't really remember what exactly what it was about. I don't want to tell you the wrong thing so. Well anyways if you missed it you should ask her to let her see if you can watch. It was really helpful.
-Then we corrected the Concept-Development Practice Page: Chapter 14: Satellite Motion
I'm really sorry about my spelling. I can't spell for squat. If anybody can't understand just leave a comment and I'll try to fix it to the best of my abilities.
I think I cover everything we did today.
Finish your chapter 8 review
TEST TUESDAY APRIL 28, 2009
The next scribe is John.
Tuesday, April 21, 2009
Gravitational Potential Energy!
Hai gaiz! Today we went over the Gravitational Potential Energy worksheet that came with the booklet notes from yesterday! Refer to the slides to get the answers ;).
I'd also like to note of where some of the masses came from, since I'm sure some of you (Does anyone even read this blog, aside from Ms. K?). For example, the first question. If you were wondering where the second mass came from, its basically the mass of the earth, and that is on the formula sheet! The radius of the earth also came from the formula sheet! I looove formula sheet!
Moving on, after finishing worksheet, we got four new handouts (one of them was a small booklet) on gravitational PE! I believe the handouts included notes, yes..yes they did. There are also some questions to work on amongst the handouts. Make sure you do them, kay?
Oh, and test is on Tuesday. Okay? Next scribe is "trips-a-lot" Jennifer. Have a good night everyone.
I'd also like to note of where some of the masses came from, since I'm sure some of you (Does anyone even read this blog, aside from Ms. K?). For example, the first question. If you were wondering where the second mass came from, its basically the mass of the earth, and that is on the formula sheet! The radius of the earth also came from the formula sheet! I looove formula sheet!
Moving on, after finishing worksheet, we got four new handouts (one of them was a small booklet) on gravitational PE! I believe the handouts included notes, yes..yes they did. There are also some questions to work on amongst the handouts. Make sure you do them, kay?
Oh, and test is on Tuesday. Okay? Next scribe is "trips-a-lot" Jennifer. Have a good night everyone.
April 20th, 2009
In class we:
ii. 3.83 x 10^-3
iv. 4.23 years
v. Ts = 0.35 Tm
ix. Fg = 8.8 x 10^-10 N
x. Fg = 6.5 x 10-8 N
xi. a) Fg = 3.13 x 10^26 N
b) Fg = 490 N
xii. m = 9.01 x 10^-21 Kg
-Ep > 0, positive value, above ground level
-Ep = 0, at ground level
-Ep< 0, negative value, below ground level
For shorter distances:
-Fg = Gm1m2/R^2
-Vector
-Inverse Square
-F α 1-R^2
-Force, measured in Newtons, N
For greater distances:
-Ep = Gm1m2/R
-Scalar
-Inverse
-E α 1/R
-Energy, measured in Joules, J
- 1) Went over the test: Circular Motion, Work, & Energy.(Ms. Kozoriz posted the corrections.)
- 2)Went over the remaining textbook problems: Chapter 8, Page 172, Questions 1-5 and 9-12.
The answers were:
i. Tj = 12 yearsii. 3.83 x 10^-3
iv. 4.23 years
v. Ts = 0.35 Tm
ix. Fg = 8.8 x 10^-10 N
x. Fg = 6.5 x 10-8 N
xi. a) Fg = 3.13 x 10^26 N
b) Fg = 490 N
xii. m = 9.01 x 10^-21 Kg
- 3) Handed out notes: Gravitational Potential Energy.
- 4) Started a question sheet: Gravitational Potential Energy Questions.
- 5) Started another question sheet: Chapter 8 Review
- 6) Discussed the Gravitational Potential Energy Well:
-Ep > 0, positive value, above ground level
-Ep = 0, at ground level
-Ep< 0, negative value, below ground level
For shorter distances:
-Fg = Gm1m2/R^2
-Vector
-Inverse Square
-F α 1-R^2
-Force, measured in Newtons, N
For greater distances:
-Ep = Gm1m2/R
-Scalar
-Inverse
-E α 1/R
-Energy, measured in Joules, J
Monday, April 20, 2009
Sunday, April 19, 2009
Wednesday, April something 2009
I think this was the day I volunteered to scribe but was, like, busy or something. Sooooo, supposedly this was the day when we did a lab. Lab was like you take a paper and cardboard thingy 2 thumbtacks a 30 cm string and then you pin a thumbtack into the paper, with the cardboard behind it so it stays...... solid... and then ummmm that would be like, the focus point, where you draw a sun
and then you put another thumbtack somewhere 5-9 cm away I think? so after you did that, make an ellipse with the string, and uhhhhhhh yeah
After that you had to figure out all this mathematical stuff and answer the question sheet thing.
I finished first, so I'm the best.
To find the force thingy majigger
I think it was like.... 1 divided by the shorter distance thing divided by the longer distance thing? Ok well the lab was all we did that day. Tah dah.
and then you put another thumbtack somewhere 5-9 cm away I think? so after you did that, make an ellipse with the string, and uhhhhhhh yeah
After that you had to figure out all this mathematical stuff and answer the question sheet thing.
I finished first, so I'm the best.
To find the force thingy majigger
I think it was like.... 1 divided by the shorter distance thing divided by the longer distance thing? Ok well the lab was all we did that day. Tah dah.
Thursday, April 16, 2009
Thursday, April 16, 2009: Newton's Law of Universal Gravitation
Hiya! Jasmin's going to scribe today because she feels like it. Today we some-what started the new unit of Universal Gravitation. To start the class we watched a video about Kepler's three Laws. We were required to take 5 to 7 notes about it and submit it to Ms. K. Ms. K. also talked about Newton's Law of Universal Gravitation. The Slide below show's the formula and the value of 'G'. Remember that 'm' has to be in kilograms and 'R' has to be in metres. To end of class off we picked up a worksheet called Chapeter 11: Gravitational Interactions and were assigned to do questions 1-5, 9-15 on page 172 in the green textbook. Enjoy! =D
Next Scribe is Joseph... or me again. Which ever comes first. =D
Next Scribe is Joseph... or me again. Which ever comes first. =D
Thursday, April 9, 2009
Wednesday, April 8, 2009
A late Scribe Post
Ahaha I was supposed to write about what happened in class on March 27, but I just had to spend my time sleeping all day on Spring Break. I made a decision to do the blog on the 2nd Saturday of Spring Break, but the blues got into me.
Summary of March 27's class:
As it was the last day before Spring Break, it was a lazy afternoon. Ms. Kozoriz gave us 3 handouts which includes: Lab Sheet, a 5-page work sheet(s), and one of those fill in the blank paragraphs. So if you were absent that day, be sure to ask Ms. K for those sheets! The Lab that we did was about Potential and Kinetic energy. Yeah about 1/4 of the class weren't present that day so I guess this was your late overview of that missed class. You didn't miss a lot of content.
See ya and good luck on the test on Monday!
Summary of March 27's class:
As it was the last day before Spring Break, it was a lazy afternoon. Ms. Kozoriz gave us 3 handouts which includes: Lab Sheet, a 5-page work sheet(s), and one of those fill in the blank paragraphs. So if you were absent that day, be sure to ask Ms. K for those sheets! The Lab that we did was about Potential and Kinetic energy. Yeah about 1/4 of the class weren't present that day so I guess this was your late overview of that missed class. You didn't miss a lot of content.
See ya and good luck on the test on Monday!
Work/Energy
HI
On Monday, we corrected Study Guide 10 and chapter 11 Study Guide. Ms.K posted the answers for the two Study Guides. She also gave us the Investigations lab and the teacher gave 2 different sheet. half of the class got 8-2 worksheet and the other half got 8-1. then on Tuesday we worked on the lab. don't forget to do the sheet.
The next scribe is jeck
On Monday, we corrected Study Guide 10 and chapter 11 Study Guide. Ms.K posted the answers for the two Study Guides. She also gave us the Investigations lab and the teacher gave 2 different sheet. half of the class got 8-2 worksheet and the other half got 8-1. then on Tuesday we worked on the lab. don't forget to do the sheet.
The next scribe is jeck
Monday, April 6, 2009
Friday, March 27, 2009
March 26, 2009.
Hi!
Today, we corrected the chapter 10 study guide and the problem 1-6 on page 330 ( duck book)
Answers (chapter 10 study guide)
Work:
force, distance, direction, w= Fd, work, force, distance, scalar, joule, newton, meter, joule,moves, force displacement.
Work and direction of force:
in the direction of, perpendicular, in the direction of, cosine,direction of motion, negative, energy, energy, motion,positive,negative.
Power:
rate, rate, energy, P=W/t, power, work, time, watt, joule,one second, kilowatt.
Answer (problem 1-6 on page 330 duck book)
1a. w= Fd (d=15cm. F= 40N)
= 40N x 0.15m
=6 N/m or 6 J.
1b. W= Fd (m= 50 kg, d=1.95m, g=9.8)
=mgd
=50kg x 9.8N/kg x 1.95m=956 J
1c. W= Fdcos25o
=120N x 4m x cos25o
=435J
2. W= Fd (a=2.5m/S2, V2= 12.5m/s, t=5s, F=5000N)
V1= V2 - at=12.5m/s - ( 2.5 m/S2 x 5s)
= 0
d=( V1+V2)/2 x t
= (0+12.5m/s)/2 x 5s
=31.25m
W= Fd
= 5000N x 31.25m
= 156250J or 1.6 x 10^5 J
3. (F= 78N , m = 10m)
angle = 90 - 35 = 550
W= Fdcos550
= 78N x 10m x cos550
= 447.4 J
4.( V1= 25 m/s, V2= 14m/s, t= 5s, m= 52000kg)
d= (V1+V2)/2 x t
= (25 + 14)/2 x 5= 97.5m
a= (V2- V1)/t
= (14 - 25)/5
= -2.2 m/S2
F=ma
= 52000 x (-2.2m/S2)
= -114400N
W= Fd
= 114400 x 97.5
= 1154000J
5a. w= Fd
= 175 x 55
= 9625 J
5b. W= A1 + A2 + A3
= (xy/2) + (xy/2) + xy
= [ (0.04 x (-20))/2] + [ (0.04 x 20)/2] + [(0.12-0.08) x 20]
= (-0.4J) + (0.4J) + (0.8J)
= 0.8J
6. ( W= 480 J, m=3 kg, g= 9.8)
W= mgd
d= W/ mg
= 480J/ 3 x 9.8
=16.3m
Today, Ms. K gave us some worksheet to work onChapter 11 study guideWorksheets on chapter 10 and 11 study guide.
The next scribe is Abbas.
Bye!
Hi!
Today, we corrected the chapter 10 study guide and the problem 1-6 on page 330 ( duck book)
Answers (chapter 10 study guide)
Work:
force, distance, direction, w= Fd, work, force, distance, scalar, joule, newton, meter, joule,moves, force displacement.
Work and direction of force:
in the direction of, perpendicular, in the direction of, cosine,direction of motion, negative, energy, energy, motion,positive,negative.
Power:
rate, rate, energy, P=W/t, power, work, time, watt, joule,one second, kilowatt.
Answer (problem 1-6 on page 330 duck book)
1a. w= Fd (d=15cm. F= 40N)
= 40N x 0.15m
=6 N/m or 6 J.
1b. W= Fd (m= 50 kg, d=1.95m, g=9.8)
=mgd
=50kg x 9.8N/kg x 1.95m=956 J
1c. W= Fdcos25o
=120N x 4m x cos25o
=435J
2. W= Fd (a=2.5m/S2, V2= 12.5m/s, t=5s, F=5000N)
V1= V2 - at=12.5m/s - ( 2.5 m/S2 x 5s)
= 0
d=( V1+V2)/2 x t
= (0+12.5m/s)/2 x 5s
=31.25m
W= Fd
= 5000N x 31.25m
= 156250J or 1.6 x 10^5 J
3. (F= 78N , m = 10m)
angle = 90 - 35 = 550
W= Fdcos550
= 78N x 10m x cos550
= 447.4 J
4.( V1= 25 m/s, V2= 14m/s, t= 5s, m= 52000kg)
d= (V1+V2)/2 x t
= (25 + 14)/2 x 5= 97.5m
a= (V2- V1)/t
= (14 - 25)/5
= -2.2 m/S2
F=ma
= 52000 x (-2.2m/S2)
= -114400N
W= Fd
= 114400 x 97.5
= 1154000J
5a. w= Fd
= 175 x 55
= 9625 J
5b. W= A1 + A2 + A3
= (xy/2) + (xy/2) + xy
= [ (0.04 x (-20))/2] + [ (0.04 x 20)/2] + [(0.12-0.08) x 20]
= (-0.4J) + (0.4J) + (0.8J)
= 0.8J
6. ( W= 480 J, m=3 kg, g= 9.8)
W= mgd
d= W/ mg
= 480J/ 3 x 9.8
=16.3m
Today, Ms. K gave us some worksheet to work onChapter 11 study guideWorksheets on chapter 10 and 11 study guide.
The next scribe is Abbas.
Bye!
Wednesday, March 25, 2009
March 25, 2009
Hello... Everybody. I do today's scribe. By the way, my name is Hao.G . hahaaaa
Today we talked something about WORK AND ENERGY.
We define kinetic energy, gravitational potential energy, and the potential energy stored in a compressed or stretched spring. If all forces are conservative, the mechanical energy of an isolated system is constant. If non-conservative forces are present, we use the work-energy theorem to equate the work done by the non-conservative forces and the change in mechanical energy. (http://theory.uwinnipeg.ca/physics/work/index.html)
we handed in a lot of stuffs like:
1) Centripetal Acceleration & Force assignment
2) Test w/ correction
3) Lab about centripetal force
Thank you Mary I copy your blog. I think somebody didn't done it, so post it again.
what we need to do today is
1)READ PAGE 101 （the green book)
2)READ UP PAGE 323-330 (DUCK BOOK)
3)DO PROBLEMS PAGE 330 1--6 (DUCK BOOK)
If you didn't take the book to home, that 's OK . I post the questions for you guys.
1. Determine the work done in each of the following cases:
a) Kicking a soccer ball forward with a force of 40N over a distance of 15 cm
b) Lifting a 50-kg barbell straight up 1.95m
c) Pulling a sled with a force of 120N at an angle of 25 degrees to the horizontal if the sled
is displaced 4.0m forward
2. A tow truck pulls a 3000-kg car form rest with a horizontal force of 5000N. The truck and
car accelerate at 2.5m/s^2 for 5.0s to reach the speed limit of 45 km/h. How much work
is done by the tow truck?
3. A wheelbarrow is pushed by a force of 78N [U 35 degrees R] over a distance of 10m. Determine the work done to move the wheelbarrow along the ground.
4. A 52,000-kg train slows form 25m/s to 14m/s in 5.0s. Calculate the work done on the train.
5. Calculate the work done in each of the following graphs
6. Determine the height form which a 3-kg axe must be dropped so that it does 480J of work to split a log resting on the ground.
In the final, I want to show you guys some videos, but I don't know how to do it. I just give you the address.
http://www.youtube.com/watch?v=2WS1sG9fhOk&feature=related
next one is Tan LM.
see you guys tomorrow
Today we talked something about WORK AND ENERGY.
We define kinetic energy, gravitational potential energy, and the potential energy stored in a compressed or stretched spring. If all forces are conservative, the mechanical energy of an isolated system is constant. If non-conservative forces are present, we use the work-energy theorem to equate the work done by the non-conservative forces and the change in mechanical energy. (http://theory.uwinnipeg.ca/physics/work/index.html)
we handed in a lot of stuffs like:
1) Centripetal Acceleration & Force assignment
2) Test w/ correction
3) Lab about centripetal force
Thank you Mary I copy your blog. I think somebody didn't done it, so post it again.
what we need to do today is
1)READ PAGE 101 （the green book)
2)READ UP PAGE 323-330 (DUCK BOOK)
3)DO PROBLEMS PAGE 330 1--6 (DUCK BOOK)
If you didn't take the book to home, that 's OK . I post the questions for you guys.
1. Determine the work done in each of the following cases:
a) Kicking a soccer ball forward with a force of 40N over a distance of 15 cm
b) Lifting a 50-kg barbell straight up 1.95m
c) Pulling a sled with a force of 120N at an angle of 25 degrees to the horizontal if the sled
is displaced 4.0m forward
2. A tow truck pulls a 3000-kg car form rest with a horizontal force of 5000N. The truck and
car accelerate at 2.5m/s^2 for 5.0s to reach the speed limit of 45 km/h. How much work
is done by the tow truck?
3. A wheelbarrow is pushed by a force of 78N [U 35 degrees R] over a distance of 10m. Determine the work done to move the wheelbarrow along the ground.
4. A 52,000-kg train slows form 25m/s to 14m/s in 5.0s. Calculate the work done on the train.
5. Calculate the work done in each of the following graphs
6. Determine the height form which a 3-kg axe must be dropped so that it does 480J of work to split a log resting on the ground.
In the final, I want to show you guys some videos, but I don't know how to do it. I just give you the address.
http://www.youtube.com/watch?v=2WS1sG9fhOk&feature=related
next one is Tan LM.
see you guys tomorrow
Tuesday, March 24, 2009
March 24, 2009
anyongheseo,,
Whew! What am I going to say? Hmm,,, what did we do today? Well, we handed in a lot of stuffs like:
1) Centripetal Acceleration & Force assignment
2) Test w/ correction
3) Lab about centripetal force (remember the lab that we did yesterday using super duper hi-tech equipments such as string, washer, rubber stopper and a timer?) ^^,
Also, Ms. K gave us some sheets to work on...
Basically, that’s it...
I guess half of the class (including me) spent their time working on the lab sheet and assignment. So there’s nothing much to say... (I’m sorry I wish I could share some more but that’s all I can remember...^^)
And oh, if I’m not mistaken, we don’t have period 5 & 6 tomorrow, right? Yaaaiiiyyeee!!! ^^,
Next scribe… Hao Gao…^^, Aja Aja Hwayting (fighting)
Whew! What am I going to say? Hmm,,, what did we do today? Well, we handed in a lot of stuffs like:
1) Centripetal Acceleration & Force assignment
2) Test w/ correction
3) Lab about centripetal force (remember the lab that we did yesterday using super duper hi-tech equipments such as string, washer, rubber stopper and a timer?) ^^,
Also, Ms. K gave us some sheets to work on...
Basically, that’s it...
I guess half of the class (including me) spent their time working on the lab sheet and assignment. So there’s nothing much to say... (I’m sorry I wish I could share some more but that’s all I can remember...^^)
And oh, if I’m not mistaken, we don’t have period 5 & 6 tomorrow, right? Yaaaiiiyyeee!!! ^^,
Next scribe… Hao Gao…^^, Aja Aja Hwayting (fighting)
Monday, March 23, 2009
Centripetal Force Lab.
hello everyone!!
ahmm,,, today in class we got our catapult project back then we did a centripetal force lab. and it was fun :)+-+Copy.jpg)
+-+Copy.jpg)
+-+paint.jpg)
Then, finally here's what we have to find during the lab.
+paint.jpg)
Also,....
.jpg)
.jpg)
That's all we did for today's class
ahmm,, for this lab. I don't know when is it due but try to finish it..
Reminder:
Centripetal Acceleration and Centripetal Force are due tomorrow...
next scribe is pretty Mary =)
ahmm,,, today in class we got our catapult project back then we did a centripetal force lab. and it was fun :)
+-+Copy.jpg)
+-+Copy.jpg)
+-+paint.jpg)
Then, finally here's what we have to find during the lab.+paint.jpg)
Also,....
.jpg)
.jpg)
That's all we did for today's classahmm,, for this lab. I don't know when is it due but try to finish it..
Reminder:
Centripetal Acceleration and Centripetal Force are due tomorrow...
next scribe is pretty Mary =)
Subscribe to:
Posts (Atom)
